杭电ACM1032

杭电ACM1032

#include <iostream>
int main()
{
 int i,j;
 int count,max;
 int n,temp;
 using namespace std;
 while (cin >> i >> j)
 {
  max=0;
  cout << i << " " << j << " " ;
  if (i>j)
  {
   temp=i;
   i=j;
   j=temp;
  }
  for (n=i;n<=j;n++)
  {
   count=1;
   temp=n;
   while (temp!=1)
   {
    count++;
    if (temp%2==1)
    {
     temp=3*temp+1;
    } 
    else
    {
     temp=temp/2;
    }
   }
   if (count>max)
   {
    max=count;
   }
  }
  cout << max << endl;
 }
 return 0;
}

该题只需注意下输出格式，其他的看懂题目就没啥大问题了.